I was in duel match Castle, and RimaVII asked me for 1v1.
http://img28.imageshack.us/img28/6/gunz064.jpg
It was a good fight. End score Kekku 10-7 RimaVII
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I was in duel match Castle, and RimaVII asked me for 1v1.
http://img28.imageshack.us/img28/6/gunz064.jpg
It was a good fight. End score Kekku 10-7 RimaVII
''It was a good fight. End score Kekku 10-7 RimaVII''
nobodys blind
idiot
Ohhh he cheated check macro medding/reloading ._.
Or he just pressed by an accident on that button.
And the macro says: medding/RELOADING
hehe anyways good fight :)
I see you wearing lots of donors noob.
Its clear that i am still the best over here rite?
gj kekku xD
Btws, i miss yall o.O
Nice Job. Rima is easy. Cocky as hell.
Warren is nr1.
Rima didn't try.
Kekku is a donor hoar.
Nitro is a fatty.
End of discussion.
Nonono wait... Kekku can barely rs :).
Kekku uc all time I saw it yesterday with Slash. He pbed from 50 meters all time and he spike every beginning of round.
Qqqqqqqqqqqqqqq
im blind wtf im saying guys?
this thread made me LOL so hard xD. all the comments i read most of them are so FUNNY lol.
if you think thats a ego thread or someone try it to make it press thanks button
kkkkkkkkkkkkkkkk
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ur another funny guy lol, u just looking for more thanks so that u can say i got thanked again and again lol.. ur also funny.
That fight is a Draw he just won 10-7 thats not Won or dropped ô.ô
And how i know Rima He is a good player i think he didnt played right .__.
HAHAHA DRAW XD!
aff
good game i guess or did i already said it ?
Ok Mr. Random Lol. FIght me with IJJI. Everyone these days need their donor items to fight. I bet you're one of those people Warren.
LMAO. a draw? please look at the numbers or go back to kindergarten to know what the difference between 10-10 and 10-7 is. XD. anyways, nice job Kekku :]
Shhh,, 10 = 7.
Let a = x-y .... b = (x + y)^2 .... c = 4(x^2 - x y + y^2) .... u = a .... v = b-c
(u+sqrt{v})^3 = u^3 +3u^2 sqrt{v}+3uv+vsqrt{v}
(u-sqrt{v})^3 = u^3 -3u^2 sqrt{v}+3uv-vsqrt{v}
(a+sqrt{b - c})^3 = a\(a^2 +3b-3c)+(3a^2 +b-c)sqrt{b-c}
(a-sqrt{b - c})^3 = a\(a^2 +3b-3c)-(3a^2 +b-c)sqrt{b - c}
3a^2 +b-c = 3(x^2 -2xy+y^2)+x^2+2xy+y^2 -4(x^2 -xy+y^2) = 0
So:
(a + \sqrt{b - c})^3 = (a - \sqrt {b - c})^3
a + \sqrt{b - c} = a - \sqrt {b - c}
\sqrt {b - c} = 0
b - c = 0
b = c
(x + y)^2 = 4 (x^2 - x y + y^2)
x^2 + 2 x y + y^2 = 4 (x^2 - x y + y^2)
-3x^2+6xy-3y^2 = 0
(x - y)^2 = 0
x - y = 0
x = y
10 = 7
haha wow Important . screw you XD
Kekku bad
Rima Mkay MKay/...