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  1. #31
    Farmer Bashy's Avatar FGunZ E.L.I.T.E Member

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    ur another funny guy lol, u just looking for more thanks so that u can say i got thanked again and again lol.. ur also funny.

  2. #32
    Killuminati's Avatar So Many Tears [Aqua]

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    That fight is a Draw he just won 10-7 thats not Won or dropped ô.ô

    And how i know Rima He is a good player i think he didnt played right .__.




  3. #33
    Xanxus's Avatar - QNal

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    Originally Posted by Organisation XIII View Post
    That fight is a Draw he just won 10-7 thats not Won or dropped ô.ô

    And how i know Rima He is a good player i think he didnt played right .__.
    Since when is 10-7 considered a draw?

  4. #34
    Historia's Avatar FGunz Legend

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    HAHAHA DRAW XD!

    aff

    good game i guess or did i already said it ?

  5. #35
    SuperKekku's Avatar Freestyler

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    Originally Posted by Xanxus View Post
    Since when is 10-7 considered a draw?
    Sigh* I he tryed, and I tryed. why does everyone complain like its draw or sum -.- I ll always post 1v1 no matter who it is. Just accept i beat him -.-

  6. #36
    Bulba's Avatar The Original Pokemon

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    Originally Posted by WARREN View Post
    Ooooo lucky i have only a SS of you joining the game and leaving else i wouldve posted and verbally owned you, but YAAA Stigma is my name and Stigma has owned Bulba GG.
    Ok Mr. Random Lol. FIght me with IJJI. Everyone these days need their donor items to fight. I bet you're one of those people Warren.

    Originally Posted by Organisation XIII View Post
    That fight is a Draw he just won 10-7 thats not Won or dropped ô.ô

    And how i know Rima He is a good player i think he didnt played right .__.
    LMAO. a draw? please look at the numbers or go back to kindergarten to know what the difference between 10-10 and 10-7 is. XD. anyways, nice job Kekku :]
    Last edited by Bulba; 07-08-2010 at 04:06 PM.

  7. #37
    Banned

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    Shhh,, 10 = 7.

    Let a = x-y .... b = (x + y)^2 .... c = 4(x^2 - x y + y^2) .... u = a .... v = b-c

    (u+sqrt{v})^3 = u^3 +3u^2 sqrt{v}+3uv+vsqrt{v}
    (u-sqrt{v})^3 = u^3 -3u^2 sqrt{v}+3uv-vsqrt{v}
    (a+sqrt{b - c})^3 = a\(a^2 +3b-3c)+(3a^2 +b-c)sqrt{b-c}
    (a-sqrt{b - c})^3 = a\(a^2 +3b-3c)-(3a^2 +b-c)sqrt{b - c}
    3a^2 +b-c = 3(x^2 -2xy+y^2)+x^2+2xy+y^2 -4(x^2 -xy+y^2) = 0
    So:
    (a + \sqrt{b - c})^3 = (a - \sqrt {b - c})^3
    a + \sqrt{b - c} = a - \sqrt {b - c}
    \sqrt {b - c} = 0
    b - c = 0
    b = c
    (x + y)^2 = 4 (x^2 - x y + y^2)
    x^2 + 2 x y + y^2 = 4 (x^2 - x y + y^2)
    -3x^2+6xy-3y^2 = 0
    (x - y)^2 = 0
    x - y = 0
    x = y
    10 = 7
    Last edited by Important; 07-08-2010 at 04:18 PM.

  8. The following user said thank you to Important for this useful post:

    Bulba (07-08-2010)

  9. #38
    Bulba's Avatar The Original Pokemon

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    haha wow Important . screw you XD

  10. #39
    Dwinna's Avatar Aciaca Beast ! <3

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    Kekku bad
    Rima Mkay MKay/...

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